Question

If a-b,a,a+b are zeroes of the polynomial f(x) = 2x3 - 6x2 + 5x - 7 find the value of a

Answer 1

→ a=1

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Answer 2

Answer:

Value of a=1

Step-by-step explanation:

Given is a-b, a and a+b are the zeroes of the polynomial $f(x)=2x^{3}-6x^{2}+5x-7$, then

sum of zeroes=$\frac{-coefficient of x^{2}}{coefficient of x^{3}}$

$a-b+a+a+b=\frac{6}{2}$

$3a=3$

$a=1$

Thus, the  value of a is equal to "1".