Question

If a-b, a and a + b are zeroes of the polynomial fix) = 2x2 - 6x2 + 5x - 7, then
value of a is​

Answer 1

Answer:-

The Required Value Of a Is $\bf\dfrac{5}{2}$.

Explanation:-

See The Attachment For Explanation.

More To Know:-

• A polynomial having the maximum power of 2 is called quadratic polynomial.

• The values of variables in a polynomial which by putting there values gives 0 are called zeroes of that polynomial.

Answer 2

Correct Question :-

If a-b, a and a + b are zeroes of the polynomial f(x) = 2x³ - 6x² + 5x - 7, then value of a is​

Given :-

2x² - 6x² + 5x - 7

To Find :-

Value of a

Solution :-

We have

p(x) = 2x³ - 6x² + 5x - 7

Now

Sum of zeroes

α + β + γ = -b/a

Where

b = 6

a = 2

α = a - b

β = a

γ = a + b

a - b + a + a + b = 6/2

(a + a + a) - (b - b) = 6/2

3a = 3

a = 3/3

a = 1

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