if (a+b)(a+b)=289 &(a-b)(a-b)=121 find (a+b)(a-b)=?
dheerajkr2002:
a+b=17 & a-b=11 then, 17×11=187
correct
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(a+b)(a+b) = 289
(a+b)^2 = 289
(a+b)^2 = 17^2
(a+b) = 17
(a-b)(a-b) = 121
(a-b)^2 = 11^2
(a-b) = 11
(a+b)(a-b) = 17 × 11= 187
please mark as brainlist please please mark as brainlist
(a+b)^2 = 289
(a+b)^2 = 17^2
(a+b) = 17
(a-b)(a-b) = 121
(a-b)^2 = 11^2
(a-b) = 11
(a+b)(a-b) = 17 × 11= 187
please mark as brainlist please please mark as brainlist
then what is (a+b)(a-b)
17 × 11 = 187
please mark as brainlist
include that in your answer
then you mark as brainlist
i can't i'm not the asker
Answered by
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Hi friend
----------------
Your answer
---------------------
Given that => (a + b)(a + b) = 289
So,
-------
(a + b)(a + b) = 289
=> (a + b)² = 289
=> (a + b) = √289
=> (a + b) = 17
Again,
------------
(a - b)(a - b) = 121
=> (a - b)² = 121
=> (a - b) = √121
=> (a - b) = 11
So,
------
(a + b)(a - b) = 17 × 11
(a + b)(a - b) = 187
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
----------------
Your answer
---------------------
Given that => (a + b)(a + b) = 289
So,
-------
(a + b)(a + b) = 289
=> (a + b)² = 289
=> (a + b) = √289
=> (a + b) = 17
Again,
------------
(a - b)(a - b) = 121
=> (a - b)² = 121
=> (a - b) = √121
=> (a - b) = 11
So,
------
(a + b)(a - b) = 17 × 11
(a + b)(a - b) = 187
HOPE IT HELPS
#ARCHITECTSETHROLLINS
✯ BRAINLY STAR ✯
Please mark my answer as brainliest
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