if |A-B|=|A|-|B| the angle between A and B is
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Answered by
1
Step-by-step explanation:
we know, |A - B| = √{|A|² + |B|² - 2|A||B|cos}
where is angel between A and B.
given, |A - B| = |A| - |B|
so, √{|A|² + |B|² - 2|A||B|cos} = |A| - |B|
squaring both sides,
|A|² + |B|² - 2|A||B|cos = |A|² + |B|² - 2|A||B|
or, -2|A||B|cos = -2|A||B|
or, cos = 1 = cos0°
hope its helpful for you.......
Answered by
1
Answer:
here,angle between A and B is 0 degree
Step-by-step explanation:
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