if |A×B|=A.B then |A+B| is equal to
Answers
Answered by
9
If we consider θ to be the angle between the vectors A and B,
by defination of cross product and dot product,
AxB= |A||B|sinθ n̂
A.B = |A||B|cosθ
Edit
Thanks for the correction from the community.
AxB is a vector and A.B is a scalar, which can't be equal. The question should have been with
| AxB | = A.B
Considering the correction,
| AxB | = A.B can be only possible when sinθ = cosθ ,
which is so for θ=π/4 radians.
Therfore, the angle between A and B is π/4
by defination of cross product and dot product,
AxB= |A||B|sinθ n̂
A.B = |A||B|cosθ
Edit
Thanks for the correction from the community.
AxB is a vector and A.B is a scalar, which can't be equal. The question should have been with
| AxB | = A.B
Considering the correction,
| AxB | = A.B can be only possible when sinθ = cosθ ,
which is so for θ=π/4 radians.
Therfore, the angle between A and B is π/4
dodo1050:
ok
Answered by
1
the answer is A+B
hope it helps u
hope it helps u
Similar questions