If a,b & C are the distinct roots, of the
equation ,x^2-x+1= 0, then a^101+b^107
equal to??
Plz don't use google
Answers
Answered by
1
look here basically I m straight away tried
with assumptions
Try with values of w
u get a=-w
b=-w^2
-w^101+(-w^214)
=-w^2+-w
=-(w^2+w)
=-(-1)
=1
with assumptions
Try with values of w
u get a=-w
b=-w^2
-w^101+(-w^214)
=-w^2+-w
=-(w^2+w)
=-(-1)
=1
Answered by
1
this is the actual method
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