If a-b and a+b and a are zeroes of polynomial 2x^3-6x^2+5x-7=0, find a
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Answered by
1
Answer:
1
Step-by-step explanation:
Sum of zeroes in a quadratic equation is
-> sum of zeroes = -(coefficient of x^2)/coefficient of x^3
i.e. -(-6)/2 = a-b + a+b + a
gives 3a = 3
a = 1
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Answered by
2
Step-by-step explanation:
in a cubic polynomial,
sum of roots=-b/a. - coff of x²/coff of x³
-(-6)/2= a+b+a-b+a
3a=3
a=1
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