Question

if (a+b) and (a-b) are the zeroes of polymonial p(x)=x2-6x+5, then find the value of a​

Answer 1

Given ;

p(x) = x² - 6x + 5

roots: --> α = (a+b)

-->β = (a-b)

Therefore we know that in a quadratic equation;

$α \: + \: β = \frac{ - b}{a}$

When on substituting the given values

$(a + \: b) + (a - b) \: = \frac{ - ( - 6)}{1}$

$2a \: = 6 \\ a \: = \: \frac{6}{2}\\ a \: = \: 3$

Hence a = 3

#answerwithquality

#BAL

Answer 2

Answer:

here a=1,b=-6,c=5

$\alpha + beta = \frac{ - b}{a} = 6 \\ \alpha×beta = \frac{c}{a} = 5$

alpha+beta=(a+b)+(a-b)

alpha×beta=(a+b)(a-b)

(a+b)+(a-b)=6

2a=6

a=3