If (a-b) and (a+b)are the zeroes of the polynomial f(x)=2x^3-6x^2+5x-7 find the value of a.
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Answer:
Value of a=1
Step-by-step explanation:
Given is a-b, a and a+b are the zeroes of the polynomial f(x)=2x^{3}-6x^{2}+5x-7, then
sum of zeroes=\frac{-coefficient of x^{2}}{coefficient of x^{3}}
a-b+a+a+b=\frac{6}{2}
3a=3
a=1
Thus, the value of a is equal to "1".
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