Math, asked by satya2004, 11 months ago

if a,b,and c are all non zeros and
a+b+c=0than prove that a2 + b2+c2/bc+ca+ba=3​

Answers

Answered by Ritiksuglan
2

Answer:

If a+b+c=0

then a3+b3+c3=3abc

a2/bc + b2/ca + c2/ab = 3

LCM of bc , ca , ab = abc

a3 + b3 + c3 / abc = 3

3abc / abc = 3

3 = 3

4.6

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Comments (9) Report

hi

hi

how it get 3abc/abc can u explain please

ya sure jus wait till i write

coz we took lcm

what

hi

hi

hi

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hotelcalifornia Virtuoso

Answer:

Hence Proved that

To find:

Prove that a square up on BC + b square Upon AC + c square Upon AB is equals to 3

Solution:

Given : a b c are non-zero and a + b + c is equals to zero  

If a + b + c = 0, then will becomes,

Taking LCM of bc , ca , ab i.e. abc

We know that the value of

Substituting this in the above expression, we get,

Thus proved that,

4.8

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Step-by-step explanation:

Hence Proved that

To find:

Prove that a square up on BC + b square Upon AC + c square Upon AB is equals to 3

Solution:

Given : a b c are non-zero and a + b + c is equals to zero  

If a + b + c = 0, then will becomes,

Taking LCM of bc , ca , ab i.e. abc

We know that the value of

Substituting this in the above expression, we get,

Thus proved that,

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