if a,b,and c are all non zeros and
a+b+c=0than prove that a2 + b2+c2/bc+ca+ba=3
Answers
Answer:
If a+b+c=0
then a3+b3+c3=3abc
a2/bc + b2/ca + c2/ab = 3
LCM of bc , ca , ab = abc
a3 + b3 + c3 / abc = 3
3abc / abc = 3
3 = 3
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hi
hi
how it get 3abc/abc can u explain please
ya sure jus wait till i write
coz we took lcm
what
hi
hi
hi
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hotelcalifornia Virtuoso
Answer:
Hence Proved that
To find:
Prove that a square up on BC + b square Upon AC + c square Upon AB is equals to 3
Solution:
Given : a b c are non-zero and a + b + c is equals to zero
If a + b + c = 0, then will becomes,
Taking LCM of bc , ca , ab i.e. abc
We know that the value of
Substituting this in the above expression, we get,
Thus proved that,
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Step-by-step explanation:
Hence Proved that
To find:
Prove that a square up on BC + b square Upon AC + c square Upon AB is equals to 3
Solution:
Given : a b c are non-zero and a + b + c is equals to zero
If a + b + c = 0, then will becomes,
Taking LCM of bc , ca , ab i.e. abc
We know that the value of
Substituting this in the above expression, we get,
Thus proved that,
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