If a, b and c are in A.P show that: (i) 4a, 4b and 4c are in A.P (ii) a + 4, b + 4 and c + 4 are in A.P.
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Step-by-step explanation:
as a b c are in AP b-a=c-b=d
d is the common difference.
so if 4a 4b 4c are in AP then 4b - 4a= 4(b-a)=4d and 4c-4b=4(c-a)=4d
as both are equal it is in ap . similarly 4+a 4+b 4+c are in AP as 4+b-4-a=4+c-4-b=d.
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