if a , b and c are in continued proportion , shiw that : a^2 +b^2/b(a+c) = b(a+c ) / b^2+ c^2
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Answer:
( a^2 + b^2 ) / b( a + c ) = b( a + c ) / ( b^2 + c^2 )
Step-by-step explanation:
We know, if x , y and z are given in continued proportion, it means :
• x / y = y / z .
Here, a , b and c are given in continued proportion, so
= > a / b = b / c
= > a x c = b x b
= > ac = b^2
Then,
= > a / b = b / c
Multiply and divide both sides by ( a + c ) :
= > { a( a + c ) } / { b( a + c ) } = { b( a + c ) } / { c( a + c ) }
= > { a^2 + ac } / { b( a + c ) } = { b( a + c ) } / { ac + c^2 }
= > ( a^2 + b^2 ) / b( a + c ) = b( a + c ) / ( b^2 + c^2 ) { from above, ac = b^2 }
Hence proved.
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