Math, asked by chsujatha406, 1 day ago

If A, B and C are interior angles of ∆ABC then show that tan (B+C /2) =cot A/2

Answers

Answered by Anonymous

3

Answer:

A+B+C=180

B+C=180o−A

2B+C=90o − 2A

tan( 2B+C )=tan(90 o − 2A )

tan( 2B+C)=cot 2A

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