Question

If a b and c are non zero,a+1/b =1 and b+1/c=1 then the value of abc is

Answer 1

Given:

$a+\frac{1}{b}=1$  $\frac{ab+1}{b} =1 \\  \therefore b= ab+1\\ b+\frac{1}{c}=1\\ \frac{bc+1}{c} \\ \therefore c=bc+1$Now substituting the values of b and c, we have

$abc = a*(ab+1)*(bc+1) =a* (ab^{2}c + ab + bc +1) \\\\ abc = a^{2} b^{2} c + a^{2}b + abc + a$

Hence, $abc = a^{2} b^{2} c + a^{2}b + abc + a$

Answer 2

Answer:

Step-by-step explanation: