If A, B and C are the angles of a ∆ABC, prove that tan(C+A/
2) = cotB/2
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The solution is given in the above attachment.
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Step-by-step explanation:
A+B+C=180
A+C=180-B
A+C/2=90-(B/2)
tan(A+C/2)=tan(90-B/2)
tan(A+C/2)=cotB/2
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