If A, B and C are the interior angles of a right-angle triangle, right-angled at B then find the value of A, given that tan 2A = cot(A – 30°) and 2A is an acute angle.
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SOLUTION:-
Using the trigonometric ratio of complementary angles,
cot (90°- A) = tan A
From this ratio, we can write the above expression as:
⇒ tan 2A = cot (90°- 2A) ….(1)
Given expression is tan 2A = cot (A – 30°) …(2)
Now, equate the equation (1) and (2), we get
cot (90°- 2A) = cot (A – 30°)
⇒ 90°- 2A = A – 30°
⇒3A = 90° + 30°
⇒3A = 120°
⇒A = 120°/ 3
⇒ A = 40°
More to know about complementary angles
Sin (90∘- θ) = Cos θ
Cos (90∘- θ) = Sin θ
Tan (90∘- θ) = Cot θ
Cosec (90∘- θ) = Sec θ
Sec (90∘- θ) = Cosec θ
Cot (90∘- θ) = Tan θ
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