if a b and c are the interior angles of triangle ABC find tan of B + c by 2
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A+B+C=180
Div 2 on bs
A+B+C/2=90
B+C/2=90-A/2
Tan(B+C by 2)=Tan(90-A/2)
Tan (B+C/2)=cot(A/2)
Hope this helps uhh:)
Div 2 on bs
A+B+C/2=90
B+C/2=90-A/2
Tan(B+C by 2)=Tan(90-A/2)
Tan (B+C/2)=cot(A/2)
Hope this helps uhh:)
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