Question

If A , B and C are three points on a line and B is between A and C then prove that AC - BC = AB using Euclid 's axiom

Answer 1

Step I: The fleece of the sheep along with a

thin layer of skin is removed from its

body [Fig. 3.8 (a)]. This process is called

shearing. Machines similar to those used

by barbers are used to shave off hair.

Usually, hair are removed during the hot

weather. This enables sheep to survive

without their protective coat of hair. The

hair provide woollen fibres. Woollen

fibres are then processed to obtain

woollen yarn. Shearing does not hurt

the sheep just as it does not hurt when

you get a hair cut or your father shaves his

beard. Do you know why? The uppermost

layer of the skin is dead. Also, the hair of

sheep grow again just as your hair does.Step II: The sheared skin with hair is

thoroughly washed in tanks to remove

grease, dust and dirt. This is called

scouring. Nowadays scouring is done

by machines [Fig. 3.8 (b) and (c)].

Step III: After scouring, sorting is done.

The hairy skin is sent to a factory where

hair of different textures are separated

or sorted.

Step IV: The small fluffy fibres, called

burrs, are picked out from the hair.

These are the same burrs whichsometimes appear on your sweaters. The

fibres are scoured again and dried. This

is the wool ready to be drawn into fibres.

Step V: The fibres can be dyed in various

colours, as the natural fleece of sheep

and goats is black, brown or white.

Step VI: The fibres are straightened,

combed and rolled into yarn

[Fig. 3.8 (d)]. The longer fibres are

made into wool for sweaters and the

shorter fibres are spun and woven

into woollen cloth.

Answer 2

✰ Euclid's Axiom :- Thing when concide with one another are equal to another.

$\sf {In \: the \: figure \: given \: above.} \\ \\ </p><p></p><p> \sf{AC \: concides \: with \: AB + \: BC} \\ \\ </p><p></p><p> \sf{So \: by \: Euclid's \: Axioms} \\ \\ \sf{AB + BC = AC} \\ \\ \sf{ \implies AB - AC = BC} \\ \\ \purple{ \therefore} \purple{ \underline{ \boxed{ \sf{AC - BC = AB}}}} \: \orange {\bf{ \bigstar}}$