Question

If a b and y are the zeros of the cubic polynomial p(x)=x³-7x²+4x-9, then a + b + y:​

Answer 1

Answer:

We have,

P(x)=x3+4x+2

Since, α,β,γ are the zeroes of this polynomial.

Now,

α+β+γ=−10=0

αβ+βγ+γα=14=4

αβγ=−12=−2

Since,

α+β1+β+γ1+γ+α1

⇒(α+β)(β+γ)(γ+α)(β+γ)(γ+α)+(α+β)(γ+α)+(α+β)(β+γ)

⇒(α+β)(β+γ)(γ+α)βγ+αβ+γ2+αγ+αγ+α2+βγ+αβ+αβ+αγ+β2+βγ

⇒(α+β)(β+γ)(γ+α)α2+β2

Step-by-step explanation:

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