If a b are rational numbers, find the value of a b in the following equality: √3-1/√3+1=a+b√3
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√3-1 /√3+1
√3-1/√3+1 × √3-1/√3-1
(√3-1)^2 / (√3)^2-(1)^2
3+1-2√3 / 3-1
4-2√3 / 2
2(2-√3)/2
2-√3
2+(-√3)
a=2
b=(-1)
√3-1/√3+1 × √3-1/√3-1
(√3-1)^2 / (√3)^2-(1)^2
3+1-2√3 / 3-1
4-2√3 / 2
2(2-√3)/2
2-√3
2+(-√3)
a=2
b=(-1)
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