Question

if (a,b) are the coordinates of the center of curvature whose curvature is k,then the equation of circle of curvature is______
(a).(x-a)²+(y-b)²=k²
(b).(x+a)²+(y+b)²=k²
(c).(x+a)²+(y+b)²=(1/k)²
(d).(x-a)²+(y-b)²=(1/k)²​

Answer 1

Step-by-step explanation:

beirjr8rmr8nrriene8e8ejeje8473jrjrrjehe7o3i4nu4j484n4hr8j446522i3b44

Answer 2

Answer:

The equation of circle with centre (a,b) and radius of curvature as k is given as                                   $(x-a)^2+(y-b)^2=k^2$  (Option a)

Step-by-step explanation:

The equation of a circle is given as

                                      $(x-a)^2+(y-b)^2=k^2$

In the above expression (a,b) is the coordinates of centre of the curve with radius of curvature as k.

So The correct answer in the above expression will be option A.