If a,b are the zeroes of the polynomial x^2-x-2 then find a quadratic polynomial whose zeroes are (2a+1) and (2b+1).
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Step-by-step explanation:
Given polynomial:
p(x)=x²-x-2
By factorisation method:
x²-2x+x-2
x(x-2)+(x-2)
(x-2)(x+1)
x=a=2
x=b=-1
2a+1=2(2)+1=5
2b+1=2(-1)+1=-2+1=-1
The two new zeroes are 5 and-1.
a+b=5-1=4
ab=-5
Formula of quadratic polynomial ;
x²-(a+b)x+ab
x²-4x-5 is the required polynomial.
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