Question

if a b are the zeros of quadratic polynomial x^2+x-2, then find
$( {\frac{1}{ a} - \frac{1}{b} })^{2}$

Answer 1

Hey friend

Here is your answer

=x²+x-2

=x²+2x-x-2

=x(x+2)-1(x+2)

=(x+2)(x-1)

x= -2 and x= 1

Therefore a= -2 and b=1

=(1/a-1/b)²

=[(-1/2)-(1/1)]²

=[(-1/2)-1)]²

=[(-1-2)/2]²

=(-3/2)²

=9/4

HOPE THIS HELPS YOU