If a, b are zero of x^2-6x+k.what is the value of k. If 3a - 2b= 20?
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a^2-6a+k=0
b^2-6b+k=0
subtracting these eq
a^2-b^2-6a+6b=0
a=20+2b/3
putting this value in eq
400+4b^2+80b-9b^2-54(20+2b)/3+6b=0
-5b^2
b^2-6b+k=0
subtracting these eq
a^2-b^2-6a+6b=0
a=20+2b/3
putting this value in eq
400+4b^2+80b-9b^2-54(20+2b)/3+6b=0
-5b^2
abhisekrout:
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How to find value of k??
solve the given eq by factorisation
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