Question

If a,b are zeroes of the quadratic polynomial(x)=x^2-(k-6) + (2k+1).Find the value of k if a+b= ab

Answer 1

Step-by-step explanation:

Given polynomial =

= x^2 - (k-6) + (2k+1)

sum of zeros = a + b = k-6/1

product of zeros = ab = 2k+1/1

a + b = ab

k - 6 = 2k + 1

k-2k = 1 + 6

-k = 7

K = -7