Question

if a,b are zeros of quaratic polynomial 4x2+4x+1 then form a quaractic polynomial whose zeros are 2a and 2b​

Answer 1

$\bold{\huge{\fbox{\color{Black}{Given}}}}$

• Zeroes are = a and b

$\bold{\huge{\fbox{\color{Black}{Find}}}}$

• Quadratic Equation Having zeroes 2a and 2b

$\bold{\huge{\fbox{\color{Black}{Solution}}}}$

We have,

$= > 4 {x}^{2} + 4x + 1 = 0 \\ = > 4 {x}^{2} + 2x + 2x + 1 = 0 \\ = > 2x(2x + 1) + 1(2x + 1) = 0 \\ = > (2x + 1)(2x + 1) = 0 \\ = > 2x + 1 = 0 \: \: or \: \: 2x + 1 = 0 \\ = > x = \frac{ - 1}{2} or \: x = \frac{ - 1}{2}$

Hence,

• Zeroes are a and b

• a = -1/2 and b = -1/2

So,

Value of

• 2a = 2 × -1/2 = -1

• 2b = 2 × -1/2 = -1

Quadratic Polynomial :-

${x}^{2} - (a + b)x + ab = 0 \\ = > {x}^{2} - ( - 1 - 1)x + ( - 1 \times - 1) = 0 \\ = > {x}^{2} + 2x + 1 = 0$

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Answer 2

$\huge{\mathcal{\blue{\underline{\underline{\pink{HeYa!!!}}}}}}$

${\large{\purple{\mathbb{ANSWER}}}}$

{At every place of equation there should be polynomial}

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