If a/b+b/a=1, (a not equal to 0 ,b not equal to 0),then the value of a3 - b3 is
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Answered by
23
Given, a/b +b/a = 1
=(a^2 + b^2)/ab=1
=a^2 + b^2 = ab-----(1)
Then a^3+ b^3 = (a+b)(a^2 +b^2-ab)
=(a+b)(ab-ab)-----(from 1)
=0
Hope it helps u...☺️❣️
Answered by
7
Answer:
0
Step-by-step explanation:
Given, a/b +b/a = 1
=(a^2 + b^2)/ab=1
=a^2 + b^2 = ab-----(1)
Then a^3+ b^3 = (a+b)(a^2 +b^2-ab)
=(a+b)(ab-ab)-----(from 1)
=0
Hope it helps you...
Pls mrk me brainliest...
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