If (a + b), b and (a - b) are in continuous proportion, show that
a^2/b^2=2
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Step-by-step explanation:
(a+b),b,(a-b) are in continued proportion
then, (a+b):b::b:(a-b)
(a+b)/b=b/(a-b)
(a+b)(a-b)=b²(by cross multiplying)
a²-b²=b²
a²/b²-b²/b²=b²/b²(dividing both side by b²)
a²/b²-1=1
a²/b²2=2(proved)
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