Question

if a/b=b/c, a, b, c>0 then show that (a2+b2)(b2+c2)(ab+bc)2​

Answer 1

Answer:

Step-by-step explanation:

I$\frac ab=\frac bc\\\\\Rightarrow b^2=ac\\\\\\LHS=(a^2+b^2)(b^2+c^2)\\\\=(a^2+ac)(ac+c^2)\\\\=ac(a+c)(a+c)\\\\=b^2(a+c)^2\\\\=(ab+bc)^2=RHS$f a/b=b/c, a, b, c >0 then show that

(a²+b²)(b²+c²)=(ab+bc)²