if a + b + c = 0 a square + b square + c square equals to 16 find a b + BC + CA
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we know(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
0=16+2(ab+bc+ca)
-16/2=ab+bc+ca
ab+bc+ca=-8
0=16+2(ab+bc+ca)
-16/2=ab+bc+ca
ab+bc+ca=-8
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