if a+b+c = 0
abc = 25
find the minimum value for
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a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca); (a+b+c)=0; a³+b³+c³-3abc=0; a³+b³+c³=3abc=3×25=75; Please mark the answer as brainliest.
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Answer:
we have a formula , if a + b + c = 0
a^3 + b^3 + c^3 = 3abc
given abc = 25
so , a^3+ b^3 + c^3 = 3(25) = 75
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