Math, asked by yash69527, 1 month ago

if a + b+c =0 and (a+b-c​

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Answered by psupriya789
0

if a + b + c =0 and (a + b - c​) x² + (b + c- a) x + (c + a - b) has real and equal root then roots are real roots

For ur easy understanding few steps below :-)

b² - 4ac = 0

(b + c - a)²  - 4 (a + b - c​) (c + a - b) = 0  

(b + c - a)² - (4a +4b - 4c) (4c + 4a - 4b) = 0

FORMULA...

(a + b - c)^{2} = a^{2} + b^{2} + c^{2}  - 2ab + 2bc - 2ca.\\

b²  + c²  + a²  - 2bc + 2ca - 2ab -  (4a +4b - 4c) (4c + 4a - 4b) = 0

b²  + c²  + a²  - 2bc + 2ca - 2ab = 0

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