if a + b+c =0 and (a+b-c
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if a + b + c =0 and (a + b - c) x² + (b + c- a) x + (c + a - b) has real and equal root then roots are real roots
For ur easy understanding few steps below :-)
b² - 4ac = 0
(b + c - a)² - 4 (a + b - c) (c + a - b) = 0
(b + c - a)² - (4a +4b - 4c) (4c + 4a - 4b) = 0
FORMULA...
b² + c² + a² - 2bc + 2ca - 2ab - (4a +4b - 4c) (4c + 4a - 4b) = 0
b² + c² + a² - 2bc + 2ca - 2ab = 0
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