Question

If a+b+c=0 and ab+bc+ca=26 find a^2+b^2+c^2

Answer 1

Answer:

-52

Step-by-step explanation:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca)

(0)^2 = a^2 + b^2 + c^2 + 2(26)

0 = a^2 + b^2 + c^2 + 52

a^2 + b^2 + c^2 = -52

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