if a + b + c = 0 find the value of A^2+B^2+C^2/C^2-AB
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Answer:
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca=0
a^2+b^2+c^2=2(-a(b+c)-bc)
from given condition:
a+b+c=0
therfore:b+c=-a
use above condition to get
a^2+b^2+c^2=2(a^2-bc)
therfore,k=2
I Hope It Will Help!
^_^
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca=0
a^2+b^2+c^2=2(-a(b+c)-bc)
from given condition:
a+b+c=0
therfore:b+c=-a
use above condition to get
a^2+b^2+c^2=2(a^2-bc)
therfore,k=2
I Hope It Will Help!
^_^
ganesh1452:
plz explain 2nd step
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