If √a+√b-√c=0 find value of ( a+b-c)^2
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√a+√b-√c=0
√a+√b=√c
squaring on both sides we get
a+b+2(√a×√b) =c
a+b+2√ab=c
a+b-c=-2√ab
(a+b-c)^2=(-2√ab) ^2
(a+b-c)^2=4ab
√a+√b=√c
squaring on both sides we get
a+b+2(√a×√b) =c
a+b+2√ab=c
a+b-c=-2√ab
(a+b-c)^2=(-2√ab) ^2
(a+b-c)^2=4ab
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