Question

if a+b+c=0 find value of (b+c)^2/bc+(c+a)^2/ca+(a+b)^2/ab

Answer 1

Given,
a + b + c = 0
b + c = (-a)
c + a = (-b)
a + b = (-c)
(b+c) ^ 2 / bc + (c + a)^2/ca + (a + b)^2/ab
= (-a)^2/bc + (-b)^2 / ca + (-c)^2/ab
= a^2 /bc + b^2 / ca + c^2 / ab