Question

if a+b+c=0 prove that a^2/bc+b^2/ab+c^2/ca=3​

Answer 1

Answer:

If a+b+c=0, then prove that a^2/bc+b^2/ab+c^2/CA=3? by definition of symmetric function, the correct question is a + b + c = 0 => a²/bc + b²/ca + c²/ab. (a³ + b³ + c³)/abc ={(a + b + c)(a² + b² + c² - ab - bc - ca) + 3abc/abc = 3abc/abc = 3.

Step-by-step explanation:

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