if a+b+c =0 show that a cube + b cube + c cube =3 ABC
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acube+bcube+ccube-3abc=(a+b+c)(asquare+bsquare+csquare-ab-bc-ca)
But a+b+c=0 so, RHS=0,acube+bcube+ccube=3abc
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This way it is proved
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