Question

If a+b+c =0 then (a+b) (b+c) (c+a) /abc

Answer 1

Step-by-step explanation:

if a+b+c = 0

then, a+b = 0-c= -c

b+c = -a

c+a = -b

ATQ,

(a+b)(b+c)(c+a)/abc

(-c)(-a)(-b)/abc

-abc/abc

=-1

hope it helps you.......

plz mark this answer as brainliest

Answer 2

An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc )

According to the question,

$a+b+c=0,$ then $\frac{(a+b)(b+c)(c+a)}{abc}$

Since, $a+b+c=0$

So, $a+b=-c, b+c=-a, c+a=-b$

So, $\frac{(a+b)(b+c)(c+a)}{abc}=\frac{(-c)(-a)(-b)}{abc}$

$=\frac{-abc}{abc}$

$=-1$