if a+b+c=0 then a3+b3+c3=3abc, then the valu of (2x-3y) 3+(3y-5z) 3(5z-2x) 3
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Step-by-step explanation:
if a+b+c=0 then a3+ b3 + c3 = 3 a b c
(2x-3y) + (3y-5z) + (5z-2x) = 0
so (2x-3y) 3+(3y-5z) 3(5z-2x) 3 = 3(2x-3y) (3y-5z) (5z-2x)
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Answer:
If A+B+C=0
then the A3+B3+C3=3abc
(2x-3y) +(3y-5z) +(5z-2x) =0
So (2x-3y) 3+(3y-5z) 3(5z-2x)3
=3(2x-3y)(3y-5z) (5z-2x) is the answer
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