If a+b+c=0 then find a³+b³+c³
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Answer:
a^3 + b^3 + c^3 = 3abc
Step-by-step explanation:
ATQ ,
If a + b + c = 0
Then ,
a + b + c = 0
a + b = - c ......... ( 1 )
( a + b )^3 = ( - c)^3
a^3 + b^3 + 3ab (a + b) = - c^3
from equation ( 1 ) a + b = - c
a^3 + b ^3 + 3ab ( -c ) = c^3
a^3 + b^3 - 3abc = - c^3
a^3 + b^3 + c^3 = 3abc
Hence ,
a^3 + b^3 + c^3 'not equal to 0'
but ,
a^3 + b^3 + c^3 'is equal to 3abc'
If you want to proove that you can also write hence prooved
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