Question

if a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc​

Answer 1

Answer:

a+b+c=0

a=−b−c ..........(1)

(a+b+c) 2=0

a+2+b+2+c

2+2(ab+bc+ca)=0

K(a 2−bc)+2(ab+bc+ca)=0

2(ab+bc+ca)=−K(a(−b−c)−bc)

⟹2(ab+bc+ca)=K(ab+bc+ca)

⟹K=2

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