Question

if a+b+c=0 then find the value of a²/bc+b²/ca+c²/ab

Answer 1

Given, 
a+b+c=0
we know that,
if a+b+c=0, then a³+b³+c³=3abc
Now,
(a²/bc)+(b²/ac)+(c²/ab)=(a³+b³+c³)/abc
                                   = 3abc/abc
                                   =3

Answer 2

Hi friend,

Given,

a + b + c = 0
Then a³ + b³ + c³ = 3abc
___________________

a²/bc + b²/ca + c²/ab

→ {a²×a + b²×b + c²×c }/abc

→ (a³+b³+c³)/abc

→ 3abc/abc

→ 3

Hope it helps ……