if a+b+c=0 then find the value of a²/bc +b²/ca +c²/ab
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Answer:
The answer is 3
Step-by-step explanation:
Given, a+b+c=0
a²/bc+b²/ca+c²/ab
=(a³+b³+c³)/abc
= (a³+b³+c³-3abc+3abc)/abc
= {(a+b+c)(a²+b²+c²-ab-bc-ac)+3abc}/abc
= {0×(a²+b²+c²-ab-bc-ac)+3abc/abc [∵ a+b+c=0]
= (0+3abc)/abc
= 3abc/abc
= 3
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