if a+b+c=0 then find the value of a3+b3+c3-3abc
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(a+b+c)³=0
(a+b)³+c³+3c(a+b)(a+b+c)=0
a³+b³+c³+3ab(a+b)+3c(a²+ab+ac+ab+b²+bc) =0
a³+b³+c³+3a²b+3ab²+3ca²+3abc+3ac²+3abc+3b²c+3bc²=0
a³+b³+c³+3a²b+3ab²+3ca²+3abc+3ac²+3abc+3b²c+3bc²=0
a³+b³+c³+3ab(a+b+c)+3ac(a+b+c)+3bc(a+b+c)-3abc=0
a³+b³+c³-3abc=0
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