if a+b+c=0 then gind the value of a^2÷bc+b^2÷ca+c^2÷ab
gabby4623:
Is that the only info given??
yes bro
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Answered by
1
= a²/bc + b²/ac + c²/ab
= a³+b³+c³/abc
= if a+b+c =0 then,
= a³+b³+c³= 3abc
= 3abc/abc
= 3
= a³+b³+c³/abc
= if a+b+c =0 then,
= a³+b³+c³= 3abc
= 3abc/abc
= 3
if this question is usefull to yoy
you
I dont understand this answer
From the 3rd line
now you can understood the answer
Nope
Ok ...now I do
You should add that: (a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)+abc]
So that =(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)−abc]
Never mind.... I did a more comprehensive answer myself
Answered by
0
Answer:3
Step-by-step explanation:
a²/bc + b²/ac + c²/ab
= a³+b³+c³/abc
We know that (YOU CAN MULTIPLTY IF OUT IF YOU'D LIKE)(a+b+c)³=(a³+b³+c³)+3[(a+b+c)(ab+ac+bc)+abc]
So, (a³+b³+c³)=(a+b+c)³ + 3[(a+b+c)(ab+ac+bc)+abc]
if a+b+c =0 then,
(a³+b³+c³)=(0)³ + 3[(0)(ab+ac+bc)+abc]
Therefore a³+b³+c³= 3abc
Back to the question... a³+b³+c³/abc = 3abc/abc= 3
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