Question

If a+b+c+=0 then prove that a^2/bc+b^2/SC+c^2/ab=3

Answer 1

ANSWER :

Given :

a+b+c=0----(1)

To prove:

a²/bc+b²/ac+c²/ab=3

Explanation:

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We know that,

if x+y+z=0 then

x³+y³+z³=3xyz------(2)

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LHS=a²/bc+b²/ac+c²/ab

=a³/abc+b³/abc+c³/abc

=(a³+b³+c³)/(abc)

=(3abc)/(abc). [from(2)]

After cancellation,we get

=3

Therefore,

If a+b+c=0 then

a²/bc+b²/ac+c²/ab=3