If a+b+c+=0 then prove that a^2/bc+b^2/SC+c^2/ab=3
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ANSWER :
Given :
a+b+c=0----(1)
To prove:
a²/bc+b²/ac+c²/ab=3
Explanation:
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We know that,
if x+y+z=0 then
x³+y³+z³=3xyz------(2)
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LHS=a²/bc+b²/ac+c²/ab
=a³/abc+b³/abc+c³/abc
=(a³+b³+c³)/(abc)
=(3abc)/(abc). [from(2)]
After cancellation,we get
=3
Therefore,
If a+b+c=0 then
a²/bc+b²/ac+c²/ab=3
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