Math, asked by ashutoshlaller, 1 year ago

please solve it and upload a pic of the answer where u have solved it

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Answers

Answered by ignitedlearner
0
a = i+j

b = j+k

c = k+i

a+b+c = 2i+2j+2k

for unit vector divide by its modules

= (2i+2j+2k)/√(2²+2²+2²)

= 2i+2j+2k/2√3

= i+j+k/√3

thus correct answer is option 2
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