please solve it and upload a pic of the answer where u have solved it
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a = i+j
b = j+k
c = k+i
a+b+c = 2i+2j+2k
for unit vector divide by its modules
= (2i+2j+2k)/√(2²+2²+2²)
= 2i+2j+2k/2√3
= i+j+k/√3
thus correct answer is option 2
b = j+k
c = k+i
a+b+c = 2i+2j+2k
for unit vector divide by its modules
= (2i+2j+2k)/√(2²+2²+2²)
= 2i+2j+2k/2√3
= i+j+k/√3
thus correct answer is option 2
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