if. a+b+c=0. then. prove that. a^3. + b^3+ c^3. = 3abc
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(a+b+c)^3 = a3 + b3 + c3 +3(a+b+c)(ab+bc+ca) - 3abc
as a+b+c is 0
0 = a3 + b3 + c3 +(0) - 3abc
a3 + b3 + c3 = 3abc
hence, proved
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