Math, asked by anish123459, 10 months ago

if. a+b+c=0. then. prove that. a^3. + b^3+ c^3. = 3abc
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Answered by Shadid10
0

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Answered by Great1508
0

(a+b+c)^3 = a3 + b3 + c3 +3(a+b+c)(ab+bc+ca) - 3abc

as a+b+c is 0

0 = a3 + b3 + c3 +(0) - 3abc

a3 + b3 + c3 = 3abc

hence, proved

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