Math, asked by Ashish229203, 1 year ago

if a+b+c=0 then the find the value of a²/bc+b²/ca+c²/ab

Answers

Answered by Sidnair1
8
a^2/bc + b^2/ac + c^2/ab
= taking lcm = abc
=(a^2 * a + b^2 * b + c^2 * c) / abc
= (a^3 + b^3 + c^3)/abc
if a+b+c = 0 then a^3 + b^3 + c^3 = 3abc
= 3 abc / abc 
= 3



Sidnair1: pls mark me the brainliest
Answered by smriti2004
9
Hope It Help you!!!!!!!

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